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1.4x^2-2.8x-945=0
a = 1.4; b = -2.8; c = -945;
Δ = b2-4ac
Δ = -2.82-4·1.4·(-945)
Δ = 5299.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.8)-\sqrt{5299.84}}{2*1.4}=\frac{2.8-\sqrt{5299.84}}{2.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.8)+\sqrt{5299.84}}{2*1.4}=\frac{2.8+\sqrt{5299.84}}{2.8} $
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